Hej, mam pytanie, wie ktos jak poprawic ponizszy kod zeby nie rzucal tego wyjatku co jest w temacie?
Kod jest dostepny pod linkiem
http://msdn2.microsoft.com/en-us/library/aa645740(vs.71).aspx#vcwlkthreadingtutorialexample4mutex
// Mutex.cs
// Mutex object example
using System;
using System.Threading;
public class MutexSample
{
static Mutex gM1;
static Mutex gM2;
const int ITERS = 100;
static AutoResetEvent Event1 = new AutoResetEvent(false);
static AutoResetEvent Event2 = new AutoResetEvent(false);
static AutoResetEvent Event3 = new AutoResetEvent(false);
static AutoResetEvent Event4 = new AutoResetEvent(false);
public static void Main(String[] args)
{
Console.WriteLine("Mutex Sample ...");
// Create Mutex initialOwned, with name of "MyMutex".
gM1 = new Mutex(true,"MyMutex");
// Create Mutex initialOwned, with no name.
gM2 = new Mutex(true);
Console.WriteLine(" - Main Owns gM1 and gM2");
AutoResetEvent[] evs = new AutoResetEvent[4];
evs[0] = Event1; // Event for t1
evs[1] = Event2; // Event for t2
evs[2] = Event3; // Event for t3
evs[3] = Event4; // Event for t4
MutexSample tm = new MutexSample( );
Thread t1 = new Thread(new ThreadStart(tm.t1Start));
Thread t2 = new Thread(new ThreadStart(tm.t2Start));
Thread t3 = new Thread(new ThreadStart(tm.t3Start));
Thread t4 = new Thread(new ThreadStart(tm.t4Start));
t1.Start( ); // Does Mutex.WaitAll(Mutex[] of gM1 and gM2)
t2.Start( ); // Does Mutex.WaitOne(Mutex gM1)
t3.Start( ); // Does Mutex.WaitAny(Mutex[] of gM1 and gM2)
t4.Start( ); // Does Mutex.WaitOne(Mutex gM2)
Thread.Sleep(2000);
Console.WriteLine(" - Main releases gM1");
gM1.ReleaseMutex( ); // t2 and t3 will end and signal
Thread.Sleep(1000);
Console.WriteLine(" - Main releases gM2");
gM2.ReleaseMutex( ); // t1 and t4 will end and signal
// Waiting until all four threads signal that they are done.
WaitHandle.WaitAll(evs);
Console.WriteLine("... Mutex Sample");
}
public void t1Start( )
{
Console.WriteLine("t1Start started, Mutex.WaitAll(Mutex[])");
Mutex[] gMs = new Mutex[2];
gMs[0] = gM1; // Create and load an array of Mutex for WaitAll call
gMs[1] = gM2;
Mutex.WaitAll(gMs); // Waits until both gM1 and gM2 are released
Thread.Sleep(2000);
Console.WriteLine("t1Start finished, Mutex.WaitAll(Mutex[]) satisfied");
Event1.Set( ); // AutoResetEvent.Set() flagging method is done
}
public void t2Start( )
{
Console.WriteLine("t2Start started, gM1.WaitOne( )");
gM1.WaitOne( ); // Waits until Mutex gM1 is released
Console.WriteLine("t2Start finished, gM1.WaitOne( ) satisfied");
Event2.Set( ); // AutoResetEvent.Set() flagging method is done
}
public void t3Start( )
{
Console.WriteLine("t3Start started, Mutex.WaitAny(Mutex[])");
Mutex[] gMs = new Mutex[2];
gMs[0] = gM1; // Create and load an array of Mutex for WaitAny call
gMs[1] = gM2;
Mutex.WaitAny(gMs); // Waits until either Mutex is released
Console.WriteLine("t3Start finished, Mutex.WaitAny(Mutex[])");
Event3.Set( ); // AutoResetEvent.Set() flagging method is done
}
public void t4Start( )
{
Console.WriteLine("t4Start started, gM2.WaitOne( )");
gM2.WaitOne( ); // Waits until Mutex gM2 is released
Console.WriteLine("t4Start finished, gM2.WaitOne( )");
Event4.Set( ); // AutoResetEvent.Set() flagging method is done
}
}
Ucze sie troche o synchronizacji i nie rozumiem czemu jest rzucany taki wyjatek. Kompilowalem to przy pomocy VisualStudio2005 jakby mialo to jakies znaczenie. Bede wdzieczny za odpowiedz.
Pozdrawiam